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Errol W.
Errol W.
User

Php coding  en

Autor: Errol W.
Visitado 1357, Seguidores 1, Compartilhado 0  

I am using this code:

<php?
$database = "databasename"
$servername = "localhost";
$username = "username";
$password = "password";

// Create connection
$conn = new mysqli($database, $servername, $username, $password);

// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";

SELECT `value` FROM `cartinvoice_addresses` WHERE `field_id` = "Name" ;
?>

If you this link dbViewer - Delta Dream (dreamfoundationmobileal.org)

Part of code is display and nothing from database.

Please help.

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16 RESPOSTAS - 8 ÚTEIS
Andreas S.
Andreas S.
Moderator
Usuário do mês DE

Is PHP included and enabled in your hoster package?
If yes, which PHP version is running on your server?

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Franz-Josef H.
Franz-Josef H.
Moderator

In the first line you forgot the semicolon, I think. Correctly it should read like

$database = "databasename";

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Publicado em de Franz-Josef H.
Errol W.
Errol W.
User
Autor

PHP version 7.3.27

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Publicado em de Errol W.
Axel  
Axel  
User

Don't forget to generate your page with PHP extension... By default it is HTML

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Publicado em de Axel  
Franz-Josef H.
Franz-Josef H.
Moderator

the given page is with php extension...

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Publicado em de Franz-Josef H.
Errol W.
Errol W.
User
Autor

The php extention is used.

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Publicado em de Errol W.
Franz-Josef H.
Franz-Josef H.
Moderator

Did you check the missing semikolon behind the $database definition?

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Publicado em de Franz-Josef H.
Errol W.
Errol W.
User
Autor

I fixed that, but made no difference.

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Publicado em de Errol W.
Errol W.
Errol W.
User
Autor

So I got rid of the connection part of the code. Now, page comes up blank.

<php?
$database = "databasename"
$servername = "localhost";
$username = "username";
$password = "password";

SELECT `value` FROM `cartinvoice_addresses` WHERE `field_id` = "Name" ;
?>

dbViewer - Delta Dream (dreamfoundationmobileal.org)

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Publicado em de Errol W.
Franz-Josef H.
Franz-Josef H.
Moderator

you defined the server name with localhost. Is that correct? It is usual that the database is on your web space with your web host or provider.

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Publicado em de Franz-Josef H.
Errol W.
Errol W.
User
Autor

I started out using the database viewer built in to X5. When setting that up, it was using localhost. I assumed I could do the same.

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Publicado em de Errol W.
Axel  
Axel  
User

Try to put the IP of your database web hosting and not the DB name wichi is not propaged into the DNS for a remote connection. Works ONLY when you try directly from the provider.

You cannot used the IP of your DB from locally testing. this one is not reachable from external ... Only localhost in this case.

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Publicado em de Axel  
Errol W.
Errol W.
User
Autor

I put in the ip address for the server name. It still comes up with a blank page.

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Publicado em de Errol W.
Axel  
Axel  
User

Into your original post the SELECT is wrong

SELECT `value` FROM `cartinvoice_addresses` WHERE `field_id` = "Name" ;

good one is:

SELECT `value` FROM `cart_invoice_addresses` WHERE `field_id` = "Name" ;

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Publicado em de Axel  
Axel  
Axel  
User

I suggest to you to test your code into a standalone PHP file without WSX5

You have many errors into your code

// Create connection - wrong syntax
$conn = new mysqli($database, $servername, $username, $password);

// First line is wrong syntax
<php?

// SELECT syntax seems wrong
SELECT `value` FROM `cartinvoice_addresses` WHERE `field_id` = "Name" ;

$result = $conn->query("SELECT 'value' .......

When your code is OK into standalone file, use it into WSX5

Enjoy!
Axel

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Publicado em de Axel  
Axel  
Axel  
User

This code is working locally without WSX5 into a PHP extension file.

<!DOCTYPE html>

<?php

$dbname = "afs_demo";
$servername = "localhost";
$username = "root";
$password = "password";

// Create connection
$mysqli = new mysqli($servername, $username, $password, $dbname);
$mysqli -> set_charset("utf8");

// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
echo "Connected successfully";


$sql = "SELECT value FROM cart_invoice_addresses WHERE field_id = 'Name'" ;

// $result = $mysqli->query($sql);
$result = mysqli_query($mysqli, $sql);


// while ($row = $result->fetch_assoc()) {
while ($row = mysqli_fetch_assoc($result)) {
echo '<br>';
echo $row['value'];
}

$mysqli->close();

?>

the displaying is:

Enjoy!
Axel

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